What does it mean to report a duplicate path

[gianlucabertaina]

@JonMikelV

SELECT ““G””.““BlocksetID””, ““G””.““ID””, ““G””.““Path””, ““G””.““Length””, ““G””.““FullHash””, ““G””.““Lastmodified””, ““G””.““FirstMetaBlockHash””, ““H””.““Hash”” AS ““MetablocklistHash”” FROM ( SELECT ““B””.““BlocksetID””, ““B””.““ID””, ““B””.““Path””, ““D””.““Length””, ““D””.““FullHash””, ““A””.““Lastmodified””, ““F””.““Hash”” AS ““FirstMetaBlockHash””, ““C””.““BlocksetID”” AS ““MetaBlocksetID”” FROM ““FilesetEntry”” A, ““File”” B, ““Metadataset”” C, ““Blockset”” D, ““BlocksetEntry”” E, ““Block”” F WHERE ““A””.““FileID”” = ““B””.““ID”” AND ““B””.““MetadataID”” = ““C””.““ID”” AND ““C””.““BlocksetID”” = ““D””.““ID”” AND ““E””.““BlocksetID”” = ““C””.““BlocksetID”” AND ““E””.““BlockID”” = ““F””.““ID”” AND ““E””.““Index”” = 0 AND (““B””.““BlocksetID”” = ? OR ““B””.““BlocksetID”” = ?) AND ““A””.““FilesetID”” = ? ) G LEFT OUTER JOIN ““BlocklistHash”” H ON ““H””.““BlocksetID”” = ““G””.““MetaBlocksetID”” ORDER BY ““G””.““Path””, ““H””.““Index””

Thank you. I used sqlitebrowser on my duplicati backup database. I had to substitute “” with " in your script. The result is however

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